Saturday, 10 August 2013

CAT previous year Question papers with best solutions(never miss this)

THIS is  the best solutions of CAT Exam previous papers:-

click on the below link and enjoy :-------------------- below link contain the link to the dowload


                                             CAT papers 1990-94

                                             CAT papers 1995-99

                                             CAT papers 2000-03

                                             CAT papers 2004-08

Quantitative Aptitude 4th Edition(full) By Arun Sharma

This is the quantitative apptitude  4th edition, many guyz have requested and wanted this ebook.....
 they were not getting this ebook for free and if they would be getting then that would be incomplete..
so here i am providing the whole book for free... have fun below is the link the book contain image of all the pages with good quality and the book is just 150mb approx. size....

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         THE LINK is provided below

Download link file:    Click me

YOU CAN ALSO CHECK THE BEST SOLUTION FOR THE CAT PREVIOUS YEAR QUESTION PAPERS YOU COULD EVER FIND ON INTERNET:

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Wednesday, 10 July 2013

15 Goa Government Websites hacked by Pakistani Hacker "H4x0r HuSsY"

A Hacker with Handle "H4x0r HuSsY" from Pakistan has managed to take control of few Indian Government websites and has defaced them. All of the hacked websites are belong to Goa State.

The affected websites includes NRI Commission of Goa(nri.goa.gov.in), Directorate of Agriculture(www.agri.goa.gov.in), Directorate of Art and Culture(artandculture.goa.gov.in/uploads/index.html), Department of Information and Publicity(artandculture.goa.gov.in/uploads/index.html), Directorate of Fire ; Emergency Service(goadfes.gov.in/media/index.php), Goa Dental College(gdch.goa.gov.in), Government Printing Press ; Stationery(goaprintingpress.gov.in).

Other affected websites: dfda.goa.gov.in, dsya.goa.gov.in, Deapartment of Labour ; Employment(labour.goa.gov.in), Captain of Ports Department(ports.goa.gov.in), River Navigation Department Goa(rnd.goa.gov.in/uploads/index.php), Department of Sainik Welfare Govt. of Goa(www.dosw.goa.gov.in), socialwelfare.goa.gov.in/media/index.php, Department of Tourism(goatourism.gov.in/images/index.php)

This is not the first time Indian websites being hacked by this hacker. In the past, he hacked into a number of Indian Government websites and left them defaced.

"We have pulled them completely down now" the spokesperson told local Media, adding that a complaint would be lodged with Goa Police's cyber cell soon.

Stuxnet worm Created by NSA and Israel, Says Edward Snowden


While it's been widely speculated that the notorious computer worm Stuxnet was the result of partnership between US and Israel, the famous NSA Whistleblower "Edward Snowden" has confirmed it.



Stuxnet was a highly-complex malware discovered in 2010, used as cyber weapon against the Iran's nuclear program.


Snowden answered a few interesting questions in an interview had with Germany's Der Spiegel Magazine.


When Interviewer asked about the NSA involvement in Stuxnet, Snowden confirmed that saying "NSA and Israel co-wrote it".


When asked about German authorities involvement in NSA surveillance system, Snowden confirmed that saying "Yes, of course. We're 1 in bed together with the Germans the same as with most other Western countries."

BRAIN TEASER PUZZLES

  1. A contractor had employed 100 labourers for a flyover construction task. He did not allow
    any woman to work without her husband. Also, atleast half the men working came with their
    wives.He paid five rupees per day to each man, four ruppes to each woman and one rupee to each child. He gave out 200 rupees every evening. How many men, women and children were working with the constructor? 
     Answer:- 16 men, 12 women and 72 children were working with the constructor.

Let's assume that there were X men, Y women and Z children working with the constructor.
Hence,

X + Y + Z = 100

5X + 4Y + Z = 200



Eliminating X and Y in turn from these equations, we get

X = 3Z - 200

Y = 300 - 4Z



As if woman works, her husband also works and atleast half the men working came with their
wives; the value of Y lies between X and X/2. Substituting these limiting values in
equations, we get



if Y = X,

300 - 4Z = 3Z - 200

7Z = 500

Z = 500/7 i.e. 71.428



if Y = X/2,

300 - 4Z = (3Z - 200)/2

600 - 8Z = 3Z - 200

11Z = 800

Z = 800/11 i.e. 72.727



But Z must be an integer, hence Z=72. Also, X=16 and Y=12

There were 16 men, 12 women and 72 children working with the constructor.


2.   Four friends - Arjan, Bhuvan, Guran and Lakha were comparing the number of sheep that they
owned.

It was found that Guran had ten more sheep than Lakha.

If Arjan gave one-third to Bhuvan, and Bhuvan gave a quarter of what he then held to Guran,
who then passed on a fifth of his holding to Lakha, they would all have an equal number of
sheep.

How many sheep did each of them possess? Give the minimal possible answer.

Answer:- Arjan, Bhuvan, Guran and Lakha had 90, 50, 55 and 45 sheep respectively.

Assume that Arjan, Bhuvan, Guran and Lakha had A, B, G and L sheep respectively. As it is
given that at the end each would have an equal number of sheep, comparing the final numbers
from the above table.



Arjan's sheep = Bhuvan's sheep

2A/3 = A/4 + 3B/4

8A = 3A + 9B

5A = 9B



Arjan's sheep = Guran's sheep

2A/3 = A/15 + B/5 + 4G/5

2A/3 = A/15 + A/9 + 4G/5 (as B=5A/9)

30A = 3A + 5A + 36G

22A = 36G

11A = 18G



Arjan's sheep = Lakha's sheep

2A/3 = A/60 + B/20 + G/5 + L

2A/3 = A/60 + A/36 + 11A/90 + L (as B=5A/9 and G=11A/18)

2A/3 = A/6 + L

A/2 = L

A = 2L



Also, it is given that Guran had ten more sheep than Lakha.

G = L + 10

11A/18 = A/2 + 10

A/9 = 10

A = 90 sheep



Thus, Arjan had 90 sheep, Bhuvan had 5A/9 i.e. 50 sheep, Guran had 11A/18 i.e. 55 sheep and
Lakha had A/2 i.e. 45 sheep.


3.  You are locked inside a room with 6 doors - A, B, C, D, E, F. Out of which 3 are Entrances
only and 3 are Exits only.

One person came in through door F and two minutes later second person came in through door
A. He said, "You will be set free, if you pass through all 6 doors, each door once only and
in correct order. Also, door A must be followed by door B or E, door B by C or E, door C by
D or F, door D by A or F, door E by B or D and door F by C or D."

After saying that they both left through door B and unlocked all doors. In which order must
you pass through the doors?

Answer:- The correct order is CFDABE

It is given that one person came in through door F and second person came in through door
A. It means that door A and door F are Entrances. Also, they both left through door B.
Hence, door B is Exit.

As Exit and Entrance should alter each other and we know two Entrances, let's assume that
the third Entrance is W. Thus, there are 6 possibilities with "_" indicating Exit.




(1) _W_A_F (2) _W_F_A (3) _F_W_A (4) _F_A_W (5) _A_W_F (6) _A_F_W



As door A must be followed by door B or E and none of them lead to the door F, (1) and (6)
are not possible.

Also, door D must be the Exit as only door D leads to the door A and door A is the
Entrance.

(2) _W_FDA (3) _F_WDA (4) _FDA_W (5) DA_W_F

Only door D and door C lead to the door F. But door D is used. Hence, door C must be the
Exit and precede door F. Also, the third Exit is B and the W must be door E.

(2) BECFDA (3) CFBEDA (4) CFDABE (5) DACEBF

But only door B leads to the door C and both are Exits. Hence, (2) and (5) are not
possible. Also, door F does not lead to door B - discard (3). Hence, the possible order is
(4) i.e. CFDABE.


4. There is a safe with a 5 digit number as the key. The 4th digit is 4 greater than the
second digit, while the 3rd digit is 3 less than the 2nd digit. The 1st digit is thrice the
last digit. There are 3 pairs whose sum is 11.

Find the number.

 Answer :-65292

As per given conditions, there are three possible combinations for 2nd, 3rd and 4th digits.
They are (3, 0, 7) or (4, 1, 8) or (5, 2, 9)

It is given that there are 3 pairs whose sum is 11. All possible pairs are (2, 9), (3, 8),
(4, 7), (5, 6). Now required number is 5 digit number and it contains 3 pairs of 11. So it
must not be having 0 and 1 in it. Hence, the only possible combination for 2nd, 3rd and 4th
digits is (5, 2, 9)

Also, 1st digit is thrice the last digit. The possible combinations are (3, 1), (6, 2) and
(9, 3), out of which only (6, 2) with (5, 2, 9) gives 3 pairs of 11. Hence, the answer is
65292.

5. A person travels on a cycle from home to church on a straight road with wind against him.
He took 4 hours to reach there.

On the way back to the home, he took 3 hours to reach as wind was in the same direction.

If there is no wind, how much time does he take to travel from home to church?

 Answer :-Let distance between home and church is D.

A person took 4 hours to reach church. So speed while travelling towards church is D/4.

Similarly, he took 3 hours to reach home. So speed while coming back is D/3.

There is a speed difference of 7*D/12, which is the wind helping person in 1 direction, &
slowing him in the other direction. Average the 2 speeds, & you have the speed that person
can travel in no wind, which is 7*D/24.

Hence, person will take D / (7*D/24) hours to travel distance D which is 24/7 hours.

Answer is 3 hours 25 minutes 42 seconds





Tuesday, 19 February 2013

FIND STUFFS IN GOOGLE EASILY....

Google is one of the powerful tool to search and it is one of the biggest weapon of the hackers(used in the Information gathering phase of the hacking or u can say penetration testing)
 It is very easy to download or search any particular file in the google..... i will not go into the deep stuff right    now... bcoz many of u folks will not understand.. so am going to keep this very simple...


HOW TO FIND ANY PDF, DOC, XLS, SQL??    


To find any particular pdf u do the following...

 First open the www.google.com then in the search box write "filetype:[file extension]  [name of the file]".... In place of name of the file u can write any file name whose pdf u wanted to download...
 Here for example i am using "filetype:pdf rs agrawal".... by entering this search u will find many pdf which has the name rs agrawal in the internet... And who knows u may be lucky to download any book related to rs agrawal......

  1. filetype:pdf rs agrawal
  2. filetype:doc rs agrawal
  3. filetype:xls rs agrawal
  4. filetype:sql rs agrawal
ex:-


FINDING A WEBSITE BY USING INTITLE??

 if u want to search a webpage with the title u want then u can use the keyword "intitle:[name the title] "
for example if u want to search the webpages which has the title "rs agrawal" then u can simply type
"intitle:rs agrawal" the whole search will be filtered by having all the pages with the title"rs agrawal"...

ex:-





SEARCHING A PARTICULAR SITE FOR INFORMATION

IF u want to search every webpage contain in a website then u have to use "site" keyword....
syntax is very simple "site:[name of the website]"

for ex: if u want to search every webpage contained in "rjit.org" website then u have to write
          "site:rjit.org"

ex:


         FINDING A WEBSITE BY USING "inurl" keyword

if u want to search the website which has keyword "achievement" in its URL then u can use the search
"inurl:[word/letter/integer]"

for ex:-inurl:achievement

              

You can also combine the above mentioned keywords like intitle, inurl, site, filetype with in a single string to get the desired results....

for ex:- if u want all the pdf files in the rjit.org website then u can use the string below:-


                                site:rjit.org filetype:pdf




In the same way u can play with the search and get the desired result by filtering by using these keywords into ur strings....